Web22 apr. 2024 · Find the values of x for which the function f(x) = 1 + 2sinx + 3cos^2x, 0 ≤ x ≤ 2π/3 is a maximum or minimum. asked Dec 2, 2024 in Limit, continuity and differentiability by Vikky01 ( 42.0k points) Web22 mrt. 2024 · x = (kpi)/2 x = +- (2pi)/3 + 2kpi Use trig identity: sin a + sin b = 2sin ((a + b)/2).cos ((a - b)/2) In this case: sin x + sin 3x = 2sin (2x).cos (x) (sin x + sin 3x ...
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Web25 mei 2024 · Trigonometry Trigonometric Identities and Equations Fundamental Identities 1 Answer marfre May 25, 2024 cos2x Explanation: Given: cot2x −cot2xcos2x Factor: cot2x(1 −cos2x) Use the Pythagorean trigonometric identity: sin2x + cos2x = 1 Rearrange the identity: sin2x = 1 −cos2x cot2x(1 − cos2x) = cot2xsin2x Use the identity: cotx = cosx sinx Web(a) find the value of R and the value of α. (4) (b) Hence solve the equation . 12 cos x – 4 sin x = 7 . for 0 ≤ x ≤ 360°, giving your answers to one decimal place. (5) (c) (i) Write down the minimum value of 12 cos x – 4 sin x. (1) (ii) Find, to 2 decimal places, the smallest positive value of x for which this minimum value occurs. (2) lg that\\u0027s
How to solve this?sinx+sin2x+sin3x=0 Socratic
WebIf 2 sin 2 x = 3 cos x. where 0 ≤ x ≤ 2 π, then find the value of x. Advertisement Remove all ads Solution The given equation is 2 sin 2 x = 3 cos x. Now, 2 sin 2 x = 3 cos x ⇒ 2 ( 1 − … WebUntitled - Free download as PDF File (.pdf), Text File (.txt) or read online for free. WebIf you simply divide both sides by cos 2 x then the problem will be really easy to solve for you. sin 2 ( x) = 3 cos 2 ( x) sin 2 ( x) cos 2 ( x) = 3 tan 2 x = 3 tan x = ± 3. From the last step, you can just arctan both sides twice, once with 3 and another with − 3 and you will have both of your answers. Share. lgthemario